On Sun, 2004-05-16 at 23:51, Guy wrote: > md2 has 4 disks with a chunk size of 128K. Since only 3 disks are used for > data, and the filesystem block size is 4K, the stride size should be > 128*3/4, or 96. > Change: > mke2fs -b 4096 -R stride=32 /dev/md2 > To: > mke2fs -b 4096 -R stride=96 /dev/md2 > > My logic: > "Stripe size" is "chunk size" times "number of data disks". > From example: > "chunk size" = 128 > "number of data disks" = "nr-raid-disks" - 1 (-2 if RAID6) I think this is incorrect. At this point I defer to the Software-RAID-HOWTO. http://www.tldp.org/HOWTO/Software-RAID-HOWTO-5.html#ss5.10 >From that document stride is chucksize/blocksize . Number of disks does not enter into it. So with a chunksize of 128, and a block size of 4 it would be: 128K/4K = 32 for stride. If this is indeed correct I will be sure to expand that area of the How-To so it is more clear. Thanks very much for your feedback. Regards, John Lange - To unsubscribe from this list: send the line "unsubscribe linux-raid" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
