Hi,I have tried it in 3 browsers (Chrome, firefox and internet explorer) and none of them has given me any image.
-Sashi Phpster wrote:
Bet the image is not readable from the web server. Bastien Sent from my iPod On Mar 7, 2009, at 5:04, Sashikanth Gurram <sashi34u@xxxxxx> wrote:Hi,Yes. But I assign the location of the image ( C:\Users\Sashikanth\Desktop\Bldgs_lots\Burruss.jpg) to the $location variable by using the mysqli_fetch_array($data) command. I send a query to the db and the result is obtained and the image location is stored into $location. So it is pretty straightforward. But I cannot understand why is it not displaying the picture after retrieving the image. Should I use any other additional commands to display the picture? Or do I need any changes in my PHP configuration file? I have checked the Config file and the ; sign infront of extension=php_gd2.dll has been removed.Thanks, SashiHello, Does something like this work on your php script? $location="..\..\Bldgs_lots\Burruss.jpg" OR $location="..\Bldgs_lots\Burruss.jpg" GR Muhsin Sashikanth Gurram wrote:This is the location where I have saved my images. /C:\Users\Sashikanth\Desktop\Bldgs_lots\Burruss.jpg /I have loaded the above location exactly into my database. But when I call it using /echo "<img src='$location' border='1' height='150' width='200' alt='$build' >";/ It is simply giving me some blank empty space, with the name of the picture in the blank space (Since I am using alt). So, as I see it, the retrieval part is working fine, but the displaying of the image is not functioning properly. I am using a WAMP server. Any kind of suggestions are welcome. Thanks, Sashi PS: For Reference, I am posting my entire code below again. The image retrieval part is towards the end of the code. /<html> <body> <form action="mysqli.php" method="post"> <br> <div align="center"> Building Name:<select name="name"> <option value=""> Select a Building</option> <option value="Military Building">Military Building</option> <option value="Monteith Hall">Monteith Hall</option> <option value="New Residence Hall-Career Services Site">New Residence Hall-Career Services Site</option> <option value="Williams Hall">Williams Hall</option> <option value="Women's Softball Field">Women's Softball Field</option> <option value="Wright House">Wright House</option> </select> </div> <input type="submit" /> </form> <img src="mysqli.php?"> <?php // Connects to your Database $host="******"; $user="*******"; $password="********"; $dbname="*********"; $cxn=mysqli_connect($host, $user, $password, $dbname) ; if (!$cxn=mysqli_connect($host, $user, $password, $dbname)) { $error=mysqli_error($cxn); echo "$error"; die(); } else { echo "Connection established successfully"; } //Define the variables for Day and Month $Today=date("l"); $Month=date("F"); $build=$_POST["name"]; $low_speed=2.5; $high_speed=4; $hour=date("G"); $minute=date("i"); if ($minute>=00 && $minute<=14) { $minute=00; } elseif ($minute>=15 && $minute<=29) { $minute=15; } elseif ($minute>=30 && $minute<=44) { $minute=30; } else { $minute=45; } $times="10:$minute"; $sql="SELECT buildingname, parking_lot_name, empty_spaces, distance, round(distance/($low_speed*60),1) AS low_time, round(distance/($high_speed*60),1) AS high_time, Location FROM buildings, buildings_lots, parkinglots, occupancy2, Image where(buildings.buildingcode=occupancy2.building AND buildings.buildingcode=buildings_lots.building_code ANDparkinglots.parking_lot_code=buildings_lots.parking_lot_code AND parkinglots.parking_lot_code=occupancy2.parking_lot AND Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build' AND month='$Month' AND day='Monday' AND Time='$times'"; $data = mysqli_query($cxn,$sql); if (!$data=mysqli_query($cxn,$sql)) { $error=mysqli_error($cxn); echo "$error"; die(); } else { echo "<br>"; echo "Query sent successfully"; } echo "<br>"; echo "<h1> PARKING LOT INFORMATION <h1>"; echo "<table border='1' cellspacing='5' cellpadding='2'>"; echo "<tr>\n <th>Building</th>\n <th>Parking Lot</th>\n <th>Estimated Number of Empty Spaces</th>\n <th>Distance (Feet)</th>\n <th>Estimated walking time to the building</th>\n </tr>\n"; while ($row=mysqli_fetch_array($data)) { extract($row); $building = $row[0]; $parking_lot = $row[1]; $Number_of_Empty_Spaces = $row[2]; $Distance = $row[3]; $time_l = $row[4]; $time_h=$row[5]; $location=$row[6]; echo "<tr>\n <td>$building</td>\n<td>$parking_lot</td>\n <td>$Number_of_Empty_Spaces</td>\n<td>$Distance</td>\n <td>$time_h - $time_l mins</td>\n <td>$location</td>\n </tr>\n"; } echo "</table>\n"; echo "<img src='$location' border='1' height='150' width='200' alt='$build' >"; ?> </body> </html>/ mrfroasty wrote:Hello,It might be something with location where the script is located and theimage.I think is normally the case if they arent on the same directory...If not you might want to try saving your image locations with somethinglike ../../image_folder/image.jpgI am not sure though as I have seen this issue on one application butit runs on LAMP P:S ../ One step back from the script location GR Muhsin Sashikanth Gurram wrote:Hi,Thanks a lot for the suggestion. It is working fine but there is someproblem. When I introduced the piece of code you have suggested intomy code, I am getting a space for the picture but nothing is there in that space. It is just blank. I do not know the reason for this. I am just attaching a picture just in case it might give you a better idea. Further, this is the piece of code I have written to display the pic./echo "<img src='$location' border='1' height='150' width='200' alt='$build' >";/ Any help would be greatly appreciated. Thanks, Sashi mrfroasty wrote:------------------------------------------------------------------------Hello,Storing only location of the image in dB wouldnt be any different thanother string/data retrieved from the dB.That means if you have somethinglike this in html documents whereby $image_location comes from the dBIt should work without ....header stuffs Example <img src="$image_location" border="1" height="150" width="200" alt="Image" ISMAP> P:S Replace $image_location with image location from your dB. GR Muhsin Sashikanth Gurram wrote:Dear all,I have been trying to retrieve the location of a image from database and display the image in the browser using PHP. I have written a sort of code for the purpose. All I am getting in my browser after using the code is a long set of ASCII characters with the following warning *Warning*: Cannot modify header information - headers already sent by(output started at C:\wamp\www\mysqli.php:65) in *C:\wamp\www\mysqli.php* on line *237 * I am herewith attaching my code. If anyone can point out the error orgive some kind of advice that would be really great. The location ofthe image is stored in a table by the name IMAGE under the column name Location and here in the code, the location is retrieved under the varibale name $Location. thanks, Sashi /<html> <body> <form action="mysqli.php" method="post"> <br> <div align="center"> Building Name:<select name="name"> <option value=""> Select a Building</option> <option value="Agnew Hall">Agnew Hall</option> <option value="Rector Field House">Rector Field House</option> <option value="Richard B. Talbot Educational Resources Center">Richard B. Talbot Educational Resources Center</option> <option value="Robeson Hall">Robeson Hall</option> <option value="Sandy Hall">Sandy Hall</option> <option value="Saunders hall">Saunders hall</option> <option value="Seitz Hall">Seitz Hall</option> <option value="Shanks Hall">Shanks Hall</option> <option value="Shultz Hall">Shultz Hall</option> <option value="Skelton Conference Center">Skelton Conference Center</option> <option value="Williams Hall">Williams Hall</option> <option value="Women's Softball Field">Women's Softball Field</option> <option value="Wright House">Wright House</option> </select> </div> <input type="submit" /> </form> <img src="mysqli.php?"> <?php // Connects to your Database $host="*******"; $user="*****"; $password="******"; $dbname="*******"; $cxn=mysqli_connect($host, $user, $password, $dbname) ; if (!$cxn=mysqli_connect($host, $user, $password, $dbname)) { $error=mysqli_error($cxn); echo "$error"; die(); } else { echo "Connection established successfully"; } //Define the variables for Day and Month $Today=date("l"); $Month=date("F"); $build=$_POST["name"]; $low_speed=2.5; $high_speed=4; $hour=date("G"); $minute=date("i"); if ($minute>=00 && $minute<=14) { $minute=00; } elseif ($minute>=15 && $minute<=29) { $minute=15; } elseif ($minute>=30 && $minute<=44) { $minute=30; } else { $minute=45; } $times="$hour:$minute";$sql="SELECT buildingname, parking_lot_name, empty_spaces, distance,round(distance/($low_speed*60),1) AS low_time, round(distance/($high_speed*60),1) AS high_time, Location FROM buildings, buildings_lots, parkinglots, occupancy2, Image where (buildings.buildingcode=occupancy2.building AND buildings.buildingcode=buildings_lots.building_code AND parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND parkinglots.parking_lot_code=occupancy2.parking_lot ANDBuildings.BuildingCode=Image.BuildingCode) AND buildingname='$build'AND month='$Month' AND day='$Today' AND Time='$times'"; $data = mysqli_query($cxn,$sql); if (!$data=mysqli_query($cxn,$sql)) { $error=mysqli_error($cxn); echo "$error"; die(); } else { echo "<br>"; echo "Query sent successfully"; } echo "<br>"; echo "<h1> PARKING LOT INFORMATION <h1>"; echo "<table border='1' cellspacing='5' cellpadding='2'>"; echo "<tr>\n <th>Building</th>\n <th>Parking Lot</th>\n <th>Estimated Number of Empty Spaces</th>\n <th>Distance (Feet)</th>\n <th>Estimated walking time to the building</th>\n </tr>\n"; while ($row=mysqli_fetch_array($data)) { extract($row); $building = $row[0]; $parking_lot = $row[1]; $Number_of_Empty_Spaces = $row[2]; $Distance = $row[3]; $time_l = $row[4]; $time_h=$row[5]; $location=$row[6]; echo "<tr>\n <td>$building</td>\n<td>$parking_lot</td>\n <td>$Number_of_Empty_Spaces</td>\n<td>$Distance</td>\n <td>$time_h - $time_l mins</td>\n <td>$location</td>\n </tr>\n"; } echo "</table>\n"; $err=1; if ($img = file_get_contents($location, FILE_BINARY)) { if ($img = imagecreatefromstring($img)) $err = 0; } if ($err) { header('Content-Type: text/html'); echo '<html><body><p style="font-size:9px">Error getting image...</p></body></html>'; } else { header('Content-Type: image/jpeg'); imagejpeg($img); imagedestroy($img); } ?> </body> </html>/ Sashikanth Gurram wrote:Hello guys, Thanks to you all for your kind replies. I will try the steps and get back to you if I encounter more problems. Thanks, Sashi Fortuno, Adam wrote:Matya,Ha, ha, ha! Thank you good friend. I did say I didn't try the code:-) AF> Please note, I haven't tried this. It just seems plausible. I apologize if I confused anyone. I just meant to show how the parameter could help retrieve a picture. I wasn't too concerned withthe particulars. Hopefully the concept is sound. If not, please doflame my note so no one attempts it. Be Well, A- -----Original Message----- From: Mattyasovszky Janos [mailto:mail@xxxxxxxx] Sent: Monday, March 02, 2009 9:29 AM To: php-db@xxxxxxxxxxxxx Subject: Re: Retrieving Image Location in MySQL Fortuno, Adam írta://Write a query to pull out the picture's path $sql = "SELECT path FROM Image WHERE ID = %s"; mysql_real_escape_string($value);Sorry, but this won't work, since you don't map the value of the escaped $value to the %s, lets say with sprintf()... Regards, Matya-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Sashikanth Gurram Graduate Research Assistant Department of Civil and Environmental Engineering Virginia Tech Blacksburg, VA 24060, USA -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Sashikanth Gurram Graduate Research Assistant Department of Civil and Environmental Engineering Virginia Tech Blacksburg, VA 24060, USA -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
