Dear all,
I have been trying to retrieve the location of a image from database and
display the image in the browser using PHP. I have written a sort of
code for the purpose. All I am getting in my browser after using the
code is a long set of ASCII characters with the following warning
*Warning*: Cannot modify header information - headers already sent by
(output started at C:\wamp\www\mysqli.php:65)
in *C:\wamp\www\mysqli.php* on line *237
*
I am herewith attaching my code. If anyone can point out the error or
give some kind of advice that would be really great. The location of the
image is stored in a table by the name IMAGE under the column name
Location and here in the code, the location is retrieved under the
varibale name $Location.
thanks,
Sashi
/<html>
<body>
<form action="mysqli.php" method="post">
<br>
<div align="center">
Building Name:<select name="name">
<option value=""> Select a Building</option>
<option value="Agnew Hall">Agnew Hall</option>
<option value="Rector Field House">Rector Field House</option>
<option value="Richard B. Talbot Educational Resources
Center">Richard B. Talbot Educational Resources Center</option>
<option value="Robeson Hall">Robeson Hall</option>
<option value="Sandy Hall">Sandy Hall</option>
<option value="Saunders hall">Saunders hall</option>
<option value="Seitz Hall">Seitz Hall</option>
<option value="Shanks Hall">Shanks Hall</option>
<option value="Shultz Hall">Shultz Hall</option>
<option value="Skelton Conference Center">Skelton Conference
Center</option>
<option value="Williams Hall">Williams Hall</option>
<option value="Women's Softball Field">Women's Softball Field</option>
<option value="Wright House">Wright House</option>
</select>
</div>
<input type="submit" />
</form>
<img src="mysqli.php?">
<?php
// Connects to your Database
$host="*******";
$user="*****";
$password="******";
$dbname="*******";
$cxn=mysqli_connect($host, $user, $password, $dbname) ;
if (!$cxn=mysqli_connect($host, $user, $password, $dbname))
{
$error=mysqli_error($cxn);
echo "$error";
die();
}
else
{
echo "Connection established successfully";
}
//Define the variables for Day and Month
$Today=date("l");
$Month=date("F");
$build=$_POST["name"];
$low_speed=2.5;
$high_speed=4;
$hour=date("G");
$minute=date("i");
if ($minute>=00 && $minute<=14)
{
$minute=00;
}
elseif ($minute>=15 && $minute<=29)
{
$minute=15;
}
elseif ($minute>=30 && $minute<=44)
{
$minute=30;
}
else
{
$minute=45;
}
$times="$hour:$minute";
$sql="SELECT buildingname, parking_lot_name, empty_spaces, distance,
round(distance/($low_speed*60),1) AS low_time,
round(distance/($high_speed*60),1) AS high_time, Location FROM
buildings, buildings_lots, parkinglots, occupancy2, Image where
(buildings.buildingcode=occupancy2.building AND
buildings.buildingcode=buildings_lots.building_code AND
parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND
parkinglots.parking_lot_code=occupancy2.parking_lot AND
Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build' AND
month='$Month' AND day='$Today' AND Time='$times'";
$data = mysqli_query($cxn,$sql);
if (!$data=mysqli_query($cxn,$sql))
{
$error=mysqli_error($cxn);
echo "$error";
die();
}
else
{
echo "<br>";
echo "Query sent successfully";
}
echo "<br>";
echo "<h1> PARKING LOT INFORMATION <h1>";
echo "<table border='1' cellspacing='5' cellpadding='2'>";
echo "<tr>\n
<th>Building</th>\n
<th>Parking Lot</th>\n
<th>Estimated Number of Empty Spaces</th>\n
<th>Distance (Feet)</th>\n
<th>Estimated walking time to the building</th>\n
</tr>\n";
while ($row=mysqli_fetch_array($data))
{
extract($row);
$building = $row[0];
$parking_lot = $row[1];
$Number_of_Empty_Spaces = $row[2];
$Distance = $row[3];
$time_l = $row[4];
$time_h=$row[5];
$location=$row[6];
echo "<tr>\n
<td>$building</td>\n
<td>$parking_lot</td>\n
<td>$Number_of_Empty_Spaces</td>\n
<td>$Distance</td>\n
<td>$time_h - $time_l mins</td>\n
<td>$location</td>\n
</tr>\n";
}
echo "</table>\n";
$err=1;
if ($img = file_get_contents($location, FILE_BINARY))
{
if ($img = imagecreatefromstring($img)) $err = 0;
}
if ($err)
{
header('Content-Type: text/html');
echo '<html><body><p style="font-size:9px">Error getting
image...</p></body></html>';
}
else
{
header('Content-Type: image/jpeg');
imagejpeg($img);
imagedestroy($img);
}
?>
</body>
</html>/
Sashikanth Gurram wrote:
Hello guys,
Thanks to you all for your kind replies. I will try the steps and get
back to you if I encounter more problems.
Thanks,
Sashi
Fortuno, Adam wrote:
Matya,
Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-)
AF> Please note, I haven't tried this. It just seems plausible.
I apologize if I confused anyone. I just meant to show how the
parameter could help retrieve a picture. I wasn't too concerned with
the particulars. Hopefully the concept is sound. If not, please do
flame my note so no one attempts it.
Be Well,
A-
-----Original Message-----
From: Mattyasovszky Janos [mailto:mail@xxxxxxxx] Sent: Monday, March
02, 2009 9:29 AM
To: php-db@xxxxxxxxxxxxx
Subject: Re: Retrieving Image Location in MySQL
Fortuno, Adam írta:
//Write a query to pull out the picture's path
$sql = "SELECT path FROM Image WHERE ID = %s";
mysql_real_escape_string($value);
Sorry, but this won't work, since you don't map the value of the
escaped $value to the %s, lets say with sprintf()...
Regards,
Matya
--
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
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