Matya, Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-) AF> Please note, I haven't tried this. It just seems plausible. I apologize if I confused anyone. I just meant to show how the parameter could help retrieve a picture. I wasn't too concerned with the particulars. Hopefully the concept is sound. If not, please do flame my note so no one attempts it. Be Well, A- -----Original Message----- From: Mattyasovszky Janos [mailto:mail@xxxxxxxx] Sent: Monday, March 02, 2009 9:29 AM To: php-db@xxxxxxxxxxxxx Subject: Re: Retrieving Image Location in MySQL Fortuno, Adam írta: > //Write a query to pull out the picture's path > $sql = "SELECT path FROM Image WHERE ID = %s"; > mysql_real_escape_string($value); Sorry, but this won't work, since you don't map the value of the escaped $value to the %s, lets say with sprintf()... Regards, Matya -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
