On 12-04-02 04:36 PM, Jay Blanchard wrote:
[snip]function getTiersJson( $company ) { $tiers = getTiers( $company ); $json = JSON_encode( $tiers ); } $tiersJson = getTiersJson( 1 ); ?> This will output JSON with the following structure:[/snip] OK, now I know I am being dense - but don't I have to add return $json; to getTiersJson() ?
yeah, *lol* in my testing I had a print_r() in the getTiersJson() so didn't notice I wasn't returning since I didn't do anything with the captured value (null without a proper return).
Cheers, Rob. -- E-Mail Disclaimer: Information contained in this message and any attached documents is considered confidential and legally protected. This message is intended solely for the addressee(s). Disclosure, copying, and distribution are prohibited unless authorized. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
