On 12-03-24 01:09 PM, Jay Blanchard wrote:
[snip]The crux of it is:
$focus =&$focus[$name];
[/snip]
It works as I expect so far. All I have to do is figure out how to make the element a name: element in the JSON. for instance an element would look like this
{
name: "Bob",
children: []
}
So the PHP array would have to look like this -
$json = array (
name => "Bob",
children => array (
name => "Angie"
)
)
and so on. This is for one of the services that will consume the JSON.
A little tweak here... a little tweak there:
<?php
//
// Establish the root.
//
$company = 1;
$query =
"SELECT DISTINCT "
." * "
."FROM "
." tiers "
."WHERE "
." company = {$company} ";
$root = array();
if( $db->query( $query ) )
{
while( ($row = $db->fetchRow()) )
{
$focus = &$root;
for( $i = 1; $i <= 14; $i++ )
{
$name = $row['tier'.$i];
if( !isset( $focus[$name] ) )
{
$focus[$name] = array
(
'name' => $name,
'children' => array(),
);
}
$focus = &$focus[$name]['children'];
}
}
}
$json = JSON_encode( $root );
?>
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