Hi,
Worked perfectly. Thank you very much.
-Sashi
Dollah Ihsan wrote:
Hi,
you are using single quotes like this?
echo ' <img src="imgtest.php?id=$building" />';
single quotes will ignore that "$building" variable.
Just concatenate it:
echo '<img src="imgtest.php?id=' . $building . '"';
or use double quotes:
echo "<img src=\"imgtest.php?id=$building\">";
It should work I think, sorry if it does not.
On Tue, Mar 10, 2009 at 8:14 AM, Sashikanth Gurram <sashi34u@xxxxxx> wrote:
Hello everyone,
Is there any way in which I can assign a variable to a query string?
Like for example, Let us say that there are two php files a.php and b.php. I
am currently using a image tag like <img src="imgtest.php?id=Williams Hall"
/> in a.php and am passing the value to another variable using
$build=$_GET['id']; in b.php. Now for this purpose, I am using the img tag
in the html part of my first file which makes it kind of static. Now if I
want to assign a variable (say $building) to 'id' in my first file, and
retrieve it using the variable $build in the second file what is the best
way to do it?
Will the command (written inside the PHP tags) echo ' <img
src="imgtest.php?id=$building />'; be of any help in performing the task. I
have actually tried this out, but it did not work for me (May be my syntax
is wrong although I have tried various combinations). So, is there a better
way or correct way of doing this (If what I have done is wrong). I have
tried to use $_session() command, but it is kind of yielding me a header
error.
Thanks,
Sashi
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
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Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
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