Thanks a lot everyone, particularly Haliphax, Nathan, Virgilio and Bob.
I will try it and will come back to you.
Thanks,
Sashi
haliphax wrote:
On Mon, Mar 9, 2009 at 10:24 AM, Sashikanth Gurram <sashi34u@xxxxxx> wrote:
Nathan Nobbe wrote:
On Mon, Mar 9, 2009 at 7:32 AM, Sashikanth Gurram <sashi34u@xxxxxx
<mailto:sashi34u@xxxxxx>> wrote:
Hi,
Yes, the problem was solved, but It did not work fine when I used
the same code in my larger file. Now it makes sense.
right, just track down where you started sending the output, and remember
if youre going to use header() calls in your scripts, that all of them must
come before sending any of the standard content.
Let me just repeat what you have said just to make sure that I did
not misread you.
So you say that the solution to this problem is to create another
php file with the image fetching header and just write an img tag
<img src="myimagescript.php?id=1234" /> in my original php file
(with the html tags).
what i explained in my first response is that youre mixing 2 different
approaches, and it was unclear what you were going for exactly. if you want
to have an image included in a page of html, then theres no need for the
header() call (refer to my first response for the remaining details). there
are however legitimate use cases for the use of header() & the
aforementioned image methods, i think between mine and some of the other
posts on this thread, its explained clearly.
This is what I have understood.
Regarding the point you have mentioned ( If you set the content
type using header() to "image/jpeg", do not use HTML tags to
display your image!),
correct
I definitely need the HTML tags, because this application works
based on the user input. So unless there is not input through a
html form, it wont work.
right, then just configure your webserver such that you can first access
the image directly via an http url, then integrate these links into your
dynamic pages as i explained in my first response.
Thanks a lot for all the patient replies. All the suggestions led me in a
positive direction. Finally, instead of using the header() in my main PHP
file (with HTML tags), I have used it in a secondary file and called it
using a tag<img src="imgtest.php">. It is working fine. But, the image I
need to display is also dynamic and needs a user input. So, is there any way
in which I can transfer a particular variable (the user input) from my main
php file (say A.php) to my secondary file containing the header () (say
B.php)
Yes. Use the Query String of your image-producing PHP script to pass
values. If you had an image tag like this:
<img src="imagescript.php?id=1234" />
Then you could grab the value of $_GET['id'] in your PHP script and
react accordingly.
HTH,
--
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
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