Re: Retrieving Image Location in PHP from MySQL

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On Mon, Mar 9, 2009 at 10:52 AM, Sashikanth Gurram <sashi34u@xxxxxx> wrote:
> haliphax wrote:
>>
>> On Mon, Mar 9, 2009 at 10:24 AM, Sashikanth Gurram <sashi34u@xxxxxx>
>> wrote:
>>
>>>
>>> Nathan Nobbe wrote:
>>>
>>>>
>>>> On Mon, Mar 9, 2009 at 7:32 AM, Sashikanth Gurram <sashi34u@xxxxxx
>>>> <mailto:sashi34u@xxxxxx>> wrote:
>>>>
>>>>   Hi,
>>>>
>>>>   Yes, the problem was solved, but It did not work fine when I used
>>>>   the same code in my larger file. Now it makes sense.
>>>>
>>>>
>>>> right, just track down where you started sending the output, and
>>>> remember
>>>> if youre going to use header() calls in your scripts, that all of them
>>>> must
>>>> come before sending any of the standard content.
>>>>
>>>>   Let me just repeat what you have said just to make sure that I did
>>>>   not misread you.
>>>>   So you say that the solution to this problem is to create another
>>>>   php file with the image fetching header and just write an img tag
>>>>    <img src="myimagescript.php?id=1234" /> in my original php file
>>>>   (with the html tags).
>>>>
>>>>
>>>> what i explained in my first response is that youre mixing 2 different
>>>> approaches, and it was unclear what you were going for exactly.  if you
>>>> want
>>>> to have an image included in a page of html, then theres no need for the
>>>> header() call (refer to my first response for the remaining details).
>>>>  there
>>>> are however legitimate use cases for the use of header() & the
>>>> aforementioned image methods, i think between mine and some of the other
>>>> posts on this thread, its explained clearly.
>>>>
>>>>   This is what I have understood.
>>>>   Regarding the point you have mentioned ( If you set the content
>>>>   type using header() to "image/jpeg", do not use HTML tags to
>>>>   display your image!),
>>>>
>>>>
>>>> correct
>>>>
>>>>   I definitely need the HTML tags, because this application works
>>>>   based on the user input. So unless there is not input through a
>>>>   html form, it wont work.
>>>>
>>>>
>>>> right, then just configure your webserver such that you can first access
>>>> the image directly via an http url, then integrate these links into your
>>>> dynamic pages as i explained in my first response.
>>>>
>>>
>>> Thanks a lot for all the patient replies. All the suggestions led me in a
>>> positive direction. Finally, instead of using the header() in my main PHP
>>> file (with HTML tags), I have used it in a secondary file and called it
>>> using  a tag<img src="imgtest.php">. It is working fine. But, the image I
>>> need to display is also dynamic and needs a user input. So, is there any
>>> way
>>> in which I can transfer a particular variable (the user input) from my
>>> main
>>> php file (say A.php) to my secondary file containing the header () (say
>>> B.php)
>>>
>>
>> Yes. Use the Query String of your image-producing PHP script to pass
>> values. If you had an image tag like this:
>>
>> <img src="imagescript.php?id=1234" />
>>
>> Then you could grab the value of $_GET['id'] in your PHP script and
>> react accordingly.
>
> Thanks a lot everyone, particularly Haliphax, Nathan, Virgilio and Bob.
>
> I will try it and will come back to you.

You're very welcome. This page [1] may help you get started. It's a
bit dated, but the information still holds true today.

1. http://whn.vdhri.net/2005/10/how_to_use_the_query_string_in_php.html


-- 
// Todd

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