Hi,
Thanks a lot for all the patient replies. All the suggestions led me in
a positive direction. Finally, instead of using the header() in my main
PHP file (with HTML tags), I have used it in a secondary file and called
it using a tag<img src="imgtest.php">. It is working fine. But, the
image I need to display is also dynamic and needs a user input. So, is
there any way in which I can transfer a particular variable (the user
input) from my main php file (say A.php) to my secondary file containing
the header () (say B.php)
Thanks,
Sashi
Nathan Nobbe wrote:
On Mon, Mar 9, 2009 at 7:32 AM, Sashikanth Gurram <sashi34u@xxxxxx
<mailto:sashi34u@xxxxxx>> wrote:
Hi,
Yes, the problem was solved, but It did not work fine when I used
the same code in my larger file. Now it makes sense.
right, just track down where you started sending the output, and
remember if youre going to use header() calls in your scripts, that
all of them must come before sending any of the standard content.
Let me just repeat what you have said just to make sure that I did
not misread you.
So you say that the solution to this problem is to create another
php file with the image fetching header and just write an img tag
<img src="myimagescript.php?id=1234" /> in my original php file
(with the html tags).
what i explained in my first response is that youre mixing 2 different
approaches, and it was unclear what you were going for exactly. if
you want to have an image included in a page of html, then theres no
need for the header() call (refer to my first response for the
remaining details). there are however legitimate use cases for the
use of header() & the aforementioned image methods, i think between
mine and some of the other posts on this thread, its explained clearly.
This is what I have understood.
Regarding the point you have mentioned ( If you set the content
type using header() to "image/jpeg", do not use HTML tags to
display your image!),
correct
I definitely need the HTML tags, because this application works
based on the user input. So unless there is not input through a
html form, it wont work.
right, then just configure your webserver such that you can first
access the image directly via an http url, then integrate these links
into your dynamic pages as i explained in my first response.
good luck,
-nathan
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Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
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