Sorry for the confusion. I am going from and asp page to a php form via a
link in the asp page. In order for the user to see the PHP page the variable
_VIEWSTATE has to be set as input hidden type. This variable is actually a
session variable. The thing is that this value should always be the same for
all the pages whether it is asp or php but when I call the value in PHP it
is not the same. Therefore, I can always see the page but if I go back and
forth again from asp to PHP I get an error the second time.
Here is what is happening I click on a ASP page with a link to the PHP form.
I see the PHP form with no problems. I submit the form and I see no problems
either. if I click on a link from PHP or try to just browse back to the asp
page I don't have a problem but If I try to go to the PHP form again from
the ASP page this is when I get the internal error and the reason is because
this _VIEWSTATE variable which is a session var is not the same for the
second time I go to the PHP form. This variable should always stay the same
if I got back and forth from PHP and ASP but I do not know how to maintain
its state when I do so. I call this variable in PHP by echoing the
$REQUEST["ESAuthCookie"] var therefore the second time I try to view this
PHP form I get the error because it requests a new one which does not match
the ASP one. Do I make any sense now? I apologize I am new at this.
Thanks again,
On 9/9/05, Mark Rees <mrees@xxxxxxxxxxxxxxxxx> wrote:
>
> Please reply to the list.
>
> I still don't understand the problem.
>
> Anyway, you have this in your ASP file:
>
> <input type="hidden" name="_VIEWSTATE" value="1"/>
>
> When you submit that form to the PHP file, you can retrieve the value with
> $_GET('_VIEWSTATE') or $_POST('_VIEWSTATE')
>
> When you "go back" to the ASP page, what do you mean? Clicking "back" in
> the browser, following a link, or submitting a form?
>
> Clicking "back" in the browser?
>
> ?
>
> following a link
>
> put variable in the querystring and retrieve it
>
> or submitting a form?
>
>
> send the variable back as a form input
>
>
> Yes, you were right on my logic. I fixed that but I went back to my
> original problem. Here is the issue. In the asp code an input type hidden
> variable is set as name="_VIEWSTATE" and the value is what in PHP is called
> as $_REQUEST["ESAuthCookie"]. Now the problem is that when I go from the asp
> page to the php page this value is reset in php so when I go back to the asp
> page and back to the php page I get an internal error because the _VIEWSTATE
> var is not the same in php as it is in asp. So how can I go from asp page to
> the php page and maintain the same variable's value?
>
> Thanks for your help it is really appreciate it.
>
>
>
>
> On 9/9/05, Mark Rees <mrees@xxxxxxxxxxxxxxxxx> wrote:
> So I have I this problem. I have asp page that has a link to a PHP page,
> when I click on the link I get the PHP with no problems but if I click
> back
> to the asp page and click on the PHP page I get a HTTP 500 Internal server
> error. If I hit the refresh button I get the php page again. The PHP page
> is
> a form when the form is submitted after the fresh reload an error "the
> directory name is invalid". Can anyone help me?
> ---------------------
> I suspect there is a problem with the logic. It sounds like the PHP page
> is
> not expecting to be called twice from the same link. More details are
> required, perhaps including some code, for a better answer.
>
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