On Friday 14 January 2005 21:35, Ferenc-Jan wrote: > Hello, > > I tried to create a raid5 set with 3 partitions and one missing device: That should work. > mdadm -C /dev/md1 -R -l5 -n4 /dev/hda3 /dev/hdc3 /dev/hdd3 missing Maybe it's in the syntax. What is that -R doing here ? > Later I want to add the fourth device with mdadm /dev/md1 -a /dev/hdb3. I do 'mdadm -a /dev/md1 /dev/hdb3'. Maybe that makes a difference ? > But this becomes a spare and I always end up with the missing drive in > sync, mdadm -D /dev/md1: > > <snip> > 3 0 0 0 sync > > I want to do this so I can use hdb to transfer data from an harddisk to > the raid5 set. Maybe this is only possible with Raid 1 sets? No, this should be possible. Many people do this. P.S.: You _are_ aware of the dangers of using raid-5 on drives that share the same IDE cable ? I see you use hda+hdb and hdc+hdd... In practise this could mean that if one drive fails you could lose all your data (unless you manually repair / reassemble the array) (Just making sure you don't make the same mistake I made...) Maarten - To unsubscribe from this list: send the line "unsubscribe linux-raid" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
