Hi JP,
Thanks for chipping in again. I have been using the following code
(after retrieving the local location of my image to the variable
$location. I am not really looking to host the pictures onto a site as
of now), which u have earlier provided me with
/
$err=1;
if ($img = file_get_contents("$location", FILE_BINARY))
{
if ($img = imagecreatefromstring($img)) $err = 0;
}
if ($err)
{
header('Content-Type: text/html');
echo '<html><body><p style="font-size:9px">Error getting
image...</p></body></html>';
}
else
{
header('Content-Type: image/jpeg');
imagejpeg($img);
imagedestroy($img);
}
/
I am just using this and nothing more, and I have been getting a warning
of sort "CANNOT MODIFY HEADER INFORMATION-HEADERS ALREADY SENT ......ON
LINE 234". I have looked about this warning online and i found that this
occurs when the output is sent to the browser before the headers. From
the look of the above code, I dont think I am sending the info to the
browser before the headers. Also, when I use the above code, I see a lot
of ASCII characters in my browser. May be, the image is encrypted into
some form and the encrypted form is being displayed instead of the
picture. Further, you have always mentioned about using
img src="picture.php?&img=1234. I did not clearly understand where to put it in the code. Is it a part of HTML code or is it a part of PHP code?
Thanks,
Sashi
Joao Gomes Madeira wrote:
Hello again Sashi
The answer provided by Mushin won't work because images are not
acessible from the outside. You can't have
<img src="C:\Users\Sashikanth\Desktop\Bldgs_lots\Burruss.jpg" ...>
because that's not a valid URL...
You can have something like
<img src="Bldgs_lots/Burruss.jpg" ...>
which when interpreted by the browser will become something like
http://yoursite/Bldgs_lots/Burruss.jpg
Now, for this to happen you need to have Bldgs_lots as a subfolder or
alias for your site.
Otherwise, there is the way I mentioned in the first place, involving a
php script just to get the image, which has to be called from within
your script, passing it the info from the database
echo '<img src="picture.php?&img=' . $location . '" border="1" height="150" width="200"
alt="' . $build . '">';
Now, I don't recommend passing local paths like this to scripts ...
Hope this helps
C ya
JP
--
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA
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