On Fri, Mar 6, 2009 at 1:06 PM, Joao Gomes Madeira <jpcg.mad@xxxxxxxxx>wrote:
> Hi Sashi:
>
> You're incurring in this error because the headers for the page have
> already been issued in the head section of your page.
> When you issue the php header() function, it will generate an error.
>
> Anyway, you are storing a path to a file in the database. My question
> is: do you want to put your images on a subfolder of your site, where
> they will become acessible through regular URLS, or you want to keep
> them private and only accessible by scripting?
>
> Cheers.
> JP
>
> -----Original Message-----
> From: Sashikanth Gurram <sashi34u@xxxxxx>
> To: php-db@xxxxxxxxxxxxx
> Subject: Re: Retrieving Image Location in MySQL
> Date: Fri, 06 Mar 2009 12:23:31 -0500
>
> Dear all,
>
> I have been trying to retrieve the location of a image from database and
> display the image in the browser using PHP. I have written a sort of
> code for the purpose. All I am getting in my browser after using the
> code is a long set of ASCII characters with the following warning
> *Warning*: Cannot modify header information - headers already sent by
> (output started at C:\wamp\www\mysqli.php:65)
> in *C:\wamp\www\mysqli.php* on line *237
> *
> I am herewith attaching my code. If anyone can point out the error or
> give some kind of advice that would be really great. The location of the
> image is stored in a table by the name IMAGE under the column name
> Location and here in the code, the location is retrieved under the
> varibale name $Location.
>
> thanks,
> Sashi
>
> /<html>
> <body>
> <form action="mysqli.php" method="post">
> <br>
> <div align="center">
> Building Name:<select name="name">
> <option value=""> Select a Building</option>
> <option value="Agnew Hall">Agnew Hall</option>
> <option value="Rector Field House">Rector Field House</option>
> <option value="Richard B. Talbot Educational Resources
> Center">Richard B. Talbot Educational Resources Center</option>
> <option value="Robeson Hall">Robeson Hall</option>
> <option value="Sandy Hall">Sandy Hall</option>
> <option value="Saunders hall">Saunders hall</option>
> <option value="Seitz Hall">Seitz Hall</option>
> <option value="Shanks Hall">Shanks Hall</option>
> <option value="Shultz Hall">Shultz Hall</option>
> <option value="Skelton Conference Center">Skelton Conference
> Center</option>
> <option value="Williams Hall">Williams Hall</option>
> <option value="Women's Softball Field">Women's Softball Field</option>
> <option value="Wright House">Wright House</option>
> </select>
> </div>
> <input type="submit" />
> </form>
> <img src="mysqli.php?">
>
> <?php
> // Connects to your Database
> $host="*******";
> $user="*****";
> $password="******";
> $dbname="*******";
> $cxn=mysqli_connect($host, $user, $password, $dbname) ;
> if (!$cxn=mysqli_connect($host, $user, $password, $dbname))
> {
> $error=mysqli_error($cxn);
> echo "$error";
> die();
> }
> else
> {
> echo "Connection established successfully";
> }
> //Define the variables for Day and Month
> $Today=date("l");
> $Month=date("F");
> $build=$_POST["name"];
> $low_speed=2.5;
> $high_speed=4;
> $hour=date("G");
> $minute=date("i");
> if ($minute>=00 && $minute<=14)
> {
> $minute=00;
> }
> elseif ($minute>=15 && $minute<=29)
> {
> $minute=15;
> }
> elseif ($minute>=30 && $minute<=44)
> {
> $minute=30;
> }
> else
> {
> $minute=45;
> }
> $times="$hour:$minute";
> $sql="SELECT buildingname, parking_lot_name, empty_spaces, distance,
> round(distance/($low_speed*60),1) AS low_time,
> round(distance/($high_speed*60),1) AS high_time, Location FROM
> buildings, buildings_lots, parkinglots, occupancy2, Image where
> (buildings.buildingcode=occupancy2.building AND
> buildings.buildingcode=buildings_lots.building_code AND
> parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND
> parkinglots.parking_lot_code=occupancy2.parking_lot AND
> Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build' AND
> month='$Month' AND day='$Today' AND Time='$times'";
> $data = mysqli_query($cxn,$sql);
> if (!$data=mysqli_query($cxn,$sql))
> {
> $error=mysqli_error($cxn);
> echo "$error";
> die();
> }
> else
> {
> echo "<br>";
> echo "Query sent successfully";
> }
> echo "<br>";
> echo "<h1> PARKING LOT INFORMATION <h1>";
> echo "<table border='1' cellspacing='5' cellpadding='2'>";
> echo "<tr>\n
> <th>Building</th>\n
> <th>Parking Lot</th>\n
> <th>Estimated Number of Empty Spaces</th>\n
> <th>Distance (Feet)</th>\n
> <th>Estimated walking time to the building</th>\n
> </tr>\n";
> while ($row=mysqli_fetch_array($data))
> {
> extract($row);
> $building = $row[0];
> $parking_lot = $row[1];
> $Number_of_Empty_Spaces = $row[2];
> $Distance = $row[3];
> $time_l = $row[4];
> $time_h=$row[5];
> $location=$row[6];
> echo "<tr>\n
> <td>$building</td>\n
> <td>$parking_lot</td>\n
> <td>$Number_of_Empty_Spaces</td>\n
> <td>$Distance</td>\n
> <td>$time_h - $time_l mins</td>\n
> <td>$location</td>\n
> </tr>\n";
> }
> echo "</table>\n";
> $err=1;
> if ($img = file_get_contents($location, FILE_BINARY))
> {
> if ($img = imagecreatefromstring($img)) $err = 0;
> }
> if ($err)
> {
> header('Content-Type: text/html');
> echo '<html><body><p style="font-size:9px">Error getting
> image...</p></body></html>';
> }
> else
> {
> header('Content-Type: image/jpeg');
> imagejpeg($img);
> imagedestroy($img);
> }
> ?>
> </body>
> </html>/
>
> Sashikanth Gurram wrote:
> > Hello guys,
> >
> > Thanks to you all for your kind replies. I will try the steps and get
> > back to you if I encounter more problems.
> >
> > Thanks,
> > Sashi
> >
> > Fortuno, Adam wrote:
> >> Matya,
> >>
> >> Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-)
> >>
> >> AF> Please note, I haven't tried this. It just seems plausible.
> >>
> >> I apologize if I confused anyone. I just meant to show how the
> >> parameter could help retrieve a picture. I wasn't too concerned with
> >> the particulars. Hopefully the concept is sound. If not, please do
> >> flame my note so no one attempts it.
> >>
> >> Be Well,
> >> A-
> >>
> >> -----Original Message-----
> >> From: Mattyasovszky Janos [mailto:mail@xxxxxxxx] Sent: Monday, March
> >> 02, 2009 9:29 AM
> >> To: php-db@xxxxxxxxxxxxx
> >> Subject: Re: Retrieving Image Location in MySQL
> >>
> >> Fortuno, Adam írta:
> >>
> >>
> >>> //Write a query to pull out the picture's path
> >>> $sql = "SELECT path FROM Image WHERE ID = %s";
> >>> mysql_real_escape_string($value);
> >>>
> >>
> >> Sorry, but this won't work, since you don't map the value of the
> >> escaped $value to the %s, lets say with sprintf()...
> >>
> >> Regards,
> >> Matya
> >>
> >>
> >
> >
>
>
> --
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> Sashikanth Gurram
> Graduate Research Assistant
> Department of Civil and Environmental Engineering
> Virginia Tech
> Blacksburg, VA 24060, USA
>
>
>
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
What I normally do is to use php to create the main page and then reference
the image in the img tag like this
<img src='get_image.php?id=1234'>
where the 1234 is the image I want to fetch. Then that page just handles the
image is something like
<?php
// database connection
$conn = mysql_connect("localhost", "user", "password")
OR DIE (mysql_error());
@mysql_select_db ($db, $conn) OR DIE (mysql_error());
$sql = "SELECT * FROM image WHERE image_id=".$_GET["id"];
$result = mysql_query ($sql, $conn);
if (mysql_num_rows ($result)>0) {
$row = @mysql_fetch_array ($result);
$image_type = $row["image_type"];
$image = $row["image"];
Header ("Content-type: $image_type");
print $image;
}
?>
--
Bastien
Cat, the other other white meat
