In your select element, modify your onchange statement to this:
onchange="document.location.href=this.value;"
- you won't need the submitform function.
HTH.
--- In php-objects@xxxxxxxxxxxxxxx, Sana Alamgeer <sanalmgr47@...> wrote:
>
>
> hello everyone
> here i have a php code
> i wantto create a link to a specific page behind the drop down list box, while data is coming from databse.
> when user clicks on any item in list, a concerned page should open in frame f4. here is the code, please correct this, or help me, partial code i m sending.
> <SCRIPT language="JavaScript">
> function submitform()
> {
> document.form1.submit();
> }
> </SCRIPT>
> =================
> <form action="<?php $_SERVER['../sana/PHP_SELF']; ?>" name="form1" method="post">
> <table width="500px" cellpadding="0" cellspacing="0" align="left">
> <tr>
> <td>
> <select name="mem_year" onchange="submitform();">
> <?php
> $sql="select id, page_name from tab_1";
> $sqlstmt=mysql_query($sql);
> echo "<option value='--'>Page Name</option>";
> while($result=mysql_fetch_array($sqlstmt)){
> echo "<option value=".$result["id"].">".$result["page_name"]."</option>";
> $i++;
> }
> ?>
> </select>
> </td>
> </tr>
> </table>
> </form>
> =====================
> <?php
> switch ($_POST['mem_year']):
> case "1":
> echo '<a href="f1.php"?target=f4></a>';
> break;
> default:
> echo "Error: Action must be either one option";
> endswitch;
> ?>
> </body>
> </html>
> SanaAlamgeer
>
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