hello everyone
here i have a php code
i wantto create a link to a specific page behind the drop down list box, while data is coming from databse.
when user clicks on any item in list, a concerned page should open in frame f4. here is the code, please correct this, or help me, partial code i m sending.
<SCRIPT language="JavaScript">
function submitform()
{
document.form1.submit();
}
</SCRIPT>
=================
<form action="<?php $_SERVER['../sana/PHP_SELF']; ?>" name="form1" method="post">
<table width="500px" cellpadding="0" cellspacing="0" align="left">
<tr>
<td>
<select name="mem_year" onchange="submitform();">
<?php
$sql="select id, page_name from tab_1";
$sqlstmt=mysql_query($sql);
echo "<option value='--'>Page Name</option>";
while($result=mysql_fetch_array($sqlstmt)){
echo "<option value=".$result["id"].">".$result["page_name"]."</option>";
$i++;
}
?>
</select>
</td>
</tr>
</table>
</form>
=====================
<?php
switch ($_POST['mem_year']):
case "1":
echo '<a href="f1.php"?target=f4></a>';
break;
default:
echo "Error: Action must be either one option";
endswitch;
?>
</body>
</html>
SanaAlamgeer
[Non-text portions of this message have been removed]
