Re: Whacky increment/assignment logic with $foo++ vs ++$foo

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At 10:20 AM +1100 10/7/09, clancy_1@xxxxxxxxxxxx wrote:
On Tue, 6 Oct 2009 14:08:14 -0400, tedd.sperling@xxxxxxxxx (tedd) wrote:

At 10:48 AM -0300 10/6/09, Martin Scotta wrote:
No matter how silly it can looks like (a = a++) it is still completely valid
code and it SHOULD run without problems.

Yeah, it's a valid as:

    $a = $a;

and does the same thing, which is nothing.

No; it's worse, because it can be interpreted in two different ways, which is demonstrated
by the fact that it gives different results in different languages.


That's true for different languages, but I was talking about php. In some languages even the variable $a wouldn't be legal.

However, you are correct that the confusion such assignments would raise would create problems as well.

Cheers,

tedd

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