Re: Whacky increment/assignment logic with $foo++ vs ++$foo

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On Tue, Oct 06, 2009 at 08:51:17AM -0400, Bob McConnell wrote:

> From: Joost [mailto:joost.t.hart@xxxxxxxxx] 
> > "Daevid Vincent" wrote:
> >>> From: Ben Dunlap [mailto:bdunlap@xxxxxxxxxxxxxxxxxx]
> 
> >	$a = $a++;
> 
> I just think this is an ambiguous line of code that wasn't thought
> through. The presence of the postfix operator makes the result
> undefined, no matter what language you are using. It will be an accident
> if you get the results you are expecting.

The behavior of the ++ operator is the invention of Kernighan and Ritchie.
I don't imagine they ever foresaw anyone doing something as silly as

a = a++;

except under the rarest of circumstances.

Paul

-- 
Paul M. Foster

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