"Daevid Vincent" wrote: > > >> -----Original Message----- >> From: Ben Dunlap [mailto:bdunlap@xxxxxxxxxxxxxxxxxx] >> Sent: Friday, October 02, 2009 2:58 PM >> To: php-general@xxxxxxxxxxxxx; Daevid Vincent >> Subject: Re: Whacky increment/assignment logic with >> $foo++ vs ++$foo >> >> > mind-blowing. What the heck /is/ supposed to happen when >> you do this: >> > >> > $a = 2; >> > $a = $a++; >> > echo $a; >> > >> > Seems like any way you slice it the output should be 3. I >> guess what's >> >> ... and, in fact, that /is/ how C behaves. The following code: >> >> int a = 2; >> a = a++; >> printf("a = [%d]\n", a); >> >> Will output "a = [3]". At least on Ubuntu 9 using gcc 4.3.3. >> >> So I retract my initial terse reply and apologize for misunderstanding >> your question. >> >> Ben > > EXACTLY! :) > > God (or diety of your choice) bless you for "getting" what I'm saying and > proving that it's not "C" like either. That just adds credence to my/our > argument. > > > d Well, Daevid, I still do appreciate the difference between $a = 1; $b = $a++; // $b should be 1 and $a = $a++; $b = $a; // $b should be 2 unless PHP manages to exhibit some overlay problem (read: bug) for $a in the 2nd case. True? joost. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
