On Tue, 6 Oct 2009 14:08:14 -0400, tedd.sperling@xxxxxxxxx (tedd) wrote: >At 10:48 AM -0300 10/6/09, Martin Scotta wrote: >>No matter how silly it can looks like (a = a++) it is still completely valid >>code and it SHOULD run without problems. > >Yeah, it's a valid as: > > $a = $a; > >and does the same thing, which is nothing. No; it's worse, because it can be interpreted in two different ways, which is demonstrated by the fact that it gives different results in different languages. >If you want a statement that does something, then use: > > $a = ++$a; > >or simply: > > $a++; > >or > > ++$a; > >Any of those will increment $a, whereas ($a = $a++;) does nothing. According to Schlossnagel "Advanced PHP programming" it is better to use ++$a, because this simply increments the variable, whereas $a++ makes a copy, and then increments the variable, so it involves additional time and memory usage. I cannot see that it would ever make a difference in the real world, but this is one of the tricks Schlossnagel advises you should use when you want the fastest possible code. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
