Re: wrong behaviour with is_subclass_of() ??

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On 19 Sep 2008, at 15:58, Johannes Mueller wrote:
Stut wrote:

outputs:
B implements I

I would expect the following output:
A implements I
B implements I

Because there is a big difference between extends and implements, one
of which being that the class is not considered to be a subclass of
an interface it implements. Seems entirely logical to me.

But B is also no subclass of I - it just implements I as well as A. So there could be two possible straight solutions:

1. Neither A nor B is a subclass of I.

2. Both A and B are subclasses of I.

A implements I therefore A *is not* a subclass of I.

B extends I therefore B *is* a subclass of I.

In the case of A it's simply stating that it implements every method defined by I.

B on the other hand does not necessarily implement the methods defined in I, but those methods will still be available on instances of B but the code in I will be used.

I don't see what's difficult to understand here.

-Stut

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http://stut.net/

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