Stut wrote:
outputs:
B implements I
I would expect the following output:
A implements I
B implements I
Because there is a big difference between extends and implements, one
of which being that the class is not considered to be a subclass of
an interface it implements. Seems entirely logical to me.
But B is also no subclass of I - it just implements I as well as A. So there
could be two possible straight solutions:
1. Neither A nor B is a subclass of I.
2. Both A and B are subclasses of I.
Johannes
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