On Fri, Mar 28, 2008 at 12:28 PM, Jason Pruim <japruim@xxxxxxxxxx> wrote: [snip!] > > $oldpasswordquery = "SELECT loginPassword, Record FROM current WHERE > loginPassword='{$oldPassHash}' AND Record='{$Record}'"; > $chpwold[] = mysqli_query($chpwpostlink, $oldpasswordquery) or > die("Sorry read failed: ". mysqli_error($chpwpostlink)); > $chpwresult = $chpwold[0]; > $chpwrow[] = mysqli_fetch_assoc($chpwresult) or die('Sorry it didn\'t > work....' .mysqli_error($chpwpostlink)); > echo $chpwrow['loginPassword']; > print_r($chpwrow); > > > The echo and the print_r are for debugging and obviously wont' be in > the final script... Here is the error that I am getting: > > [Fri Mar 28 12:14:39 2008] [error] PHP Notice: Undefined index: > loginPassword in /Volumes/RAIDer/webserver/Documents/dev/OLDBv2/admin/ > chpwpost.php on line 18 [snip!] Let's explain this a bit.... $chpwrow[] = mysqli_fetch_assoc($chpwresult) // .... The response from mysqli_fetch_assoc() will be an array already. You're then adding this into the $chpwrow[] array, which creates a nested array. So to call it from your example, you'd need $chpwrow[0]['loginPassword']. -- </Daniel P. Brown> Forensic Services, Senior Unix Engineer 1+ (570-) 362-0283 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php