That's because your loginpassWord is in another array. try $chpwrow[0]['loginPassword'] -----Mensagem original----- De: Jason Pruim [mailto:japruim@xxxxxxxxxx] Enviada em: sexta-feira, 28 de março de 2008 13:29 Para: [php] PHP General List Assunto: why won't my array work? Hi everyone :) Happy friday to all of you! Here's my issues, I am attempting to echo the results of mysqli query out to my script just so I can make sure it's working right, what I'm hoping to do in the long run is compare what was typed in a text box to this info... It's for verifying a old password before changing to a new password... So here is my query: $oldpasswordquery = "SELECT loginPassword, Record FROM current WHERE loginPassword='{$oldPassHash}' AND Record='{$Record}'"; $chpwold[] = mysqli_query($chpwpostlink, $oldpasswordquery) or die("Sorry read failed: ". mysqli_error($chpwpostlink)); $chpwresult = $chpwold[0]; $chpwrow[] = mysqli_fetch_assoc($chpwresult) or die('Sorry it didn\'t work....' .mysqli_error($chpwpostlink)); echo $chpwrow['loginPassword']; print_r($chpwrow); The echo and the print_r are for debugging and obviously wont' be in the final script... Here is the error that I am getting: [Fri Mar 28 12:14:39 2008] [error] PHP Notice: Undefined index: loginPassword in /Volumes/RAIDer/webserver/Documents/dev/OLDBv2/admin/ chpwpost.php on line 18 Line 18 is where the echo is... the print_r though shows this: Array ( [0] => Array ( [loginPassword] => 42205baa2581d3fcd8d8f9c6b9746a1f [Record] => 2 ) ) So why can't I access it via $chpwrow['loginPassword']? I'm stumped.... Anyone that can help me has a free beer waiting for them the next time they are in my town! :) -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 3251 132nd ave Holland, MI, 49424-9337 www.raoset.com japruim@xxxxxxxxxx -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
