Help converting C to PHP

[Tom Atkinson <nibbler@xxxxxxxxxxxxxxxxxxxxxx>]

Hello,

I am attempting to convert this code for generating the digits of pi 
from the original C (below) to PHP.

 long k=4e3,p,a[337],q,t=1e3;
  main(j){for(;a[j=q=0]+=2,--k;)
  for(p=1+2*k;j<337;q=a[j]*k+q%p*t,a[j++]=q/p)
  k!=j>2?:printf("%.3d",a[j-2]%t+q/p/t);}

I converted this to a more readable form:

long k=4e3;
int p;
int a[337];
int q;
int t=1e3;

main(j){
  for(;a[j=q=0]+=2,--k;){
    for(p=1+(2*k);j<337;q=(a[j]*k)+((q%p)*t),a[j++]=(q/p)){
      if (j>2 && k==1) printf("%.3d",(a[j-2]%t)+((q/p)/t));
    }
  }
}

and then changed it to PHP syntax

$k=4e3;
$p=0;
$a=array();
$q=0;
$t=1e3;

for(;$a[$j=$q=0]+=2,--$k;){
  for($p=1+(2*$k);$j<337;$q=($a[$j]*$k)+(($q%$p)*$t),$a[$j++]=($q/$p)){
    if ($j>2 && $k==1) printf("%.3d",($a[$j-2]%$t)+(($q/$p)/$t));
  }
}

The C code correctly gives me pi, but the PHP code gives me some other 
number which is not pi.

What am I missing?

Tom.

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