I have solved the problem. The variables are declared as and forced to
remain integers in C but PHP converts them to float during division.
This messed up the maths. Also there was a slight difference in
formatting for printf().
Tom Atkinson wrote:
Hello,
I am attempting to convert this code for generating the digits of pi
from the original C (below) to PHP.
long k=4e3,p,a[337],q,t=1e3;
main(j){for(;a[j=q=0]+=2,--k;)
for(p=1+2*k;j<337;q=a[j]*k+q%p*t,a[j++]=q/p)
k!=j>2?:printf("%.3d",a[j-2]%t+q/p/t);}
I converted this to a more readable form:
long k=4e3;
int p;
int a[337];
int q;
int t=1e3;
main(j){
for(;a[j=q=0]+=2,--k;){
for(p=1+(2*k);j<337;q=(a[j]*k)+((q%p)*t),a[j++]=(q/p)){
if (j>2 && k==1) printf("%.3d",(a[j-2]%t)+((q/p)/t));
}
}
}
and then changed it to PHP syntax
$k=4e3;
$p=0;
$a=array();
$q=0;
$t=1e3;
for(;$a[$j=$q=0]+=2,--$k;){
for($p=1+(2*$k);$j<337;$q=($a[$j]*$k)+(($q%$p)*$t),$a[$j++]=($q/$p)){
if ($j>2 && $k==1) printf("%.3d",($a[$j-2]%$t)+(($q/$p)/$t));
}
}
The C code correctly gives me pi, but the PHP code gives me some other
number which is not pi.
What am I missing?
Tom.
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