Chris -----Original Message----- From: owner-photoforum@xxxxxxxxxxxxxxxxxx [mailto:owner-photoforum@xxxxxxxxxxxxxxxxxx] On Behalf Of ADavidhazy Sent: 17 January 2011 02:05 To: List for Photo/Imaging Educators - Professionals - Students Subject: Re: Sample exam for your amusement Karl, Chris, David, Want to teach my course? ;) OK - I'll pick on Karl's note - let me know if I am missing interesting (????) questions ... 2. 33 1/3 RPM is that not exactly 200 degrees/sec. ? ;) 33.333 RPM = 33.33 x 360 /60 degrees/sec. = yes 200 degrees/se would you consider #18 again? Or help me clarify the question? The blur length gets smaller as the magnification is reduced that makes it appear sharper. Try it! If an object is d feet away and is moving at v feet/sec and the shutter speed is s seconds then the object moves through an angle of vs/d radians approximately so with a focal length of f feet the movement blur is fvs/d feet so as f gets smaller then the blur length is reduced and thus is less visible if fvs/s<circle of confusion then the image appears perfectly sharp to the eye. 19. Capacitance and Voltage Chris: watt seconds agreed! 33. High frame rate, high sensitivity and high resolution. on #35 I was going for the simple answer - computer nerds!! :) on #37 hs digital cameras fill up a buffer with images and then they start replacing from oldest until buffer filled again so if you stop recording when an event happens it runs for maybe 1/2 the buffer longer and then stops. On playback you can play back frames that were recorded before the stop signal arrived and thus look into the past! ;) ... so to speak! 30. 3.33 } These depend on your definition of terms that I do not know. 31. 1/10X ;) } If time magnification means the degree that the movement seems slower, then the capture rate to slow the movement will be higher than the display rate. The same applies to 31. major errors on my part? let me know 'cause I still have time to fix them before giving to students tomorrow afternoon! Andy Chris
