oh is it, can u explain, how to find out it.....which portion of the code. i see only this,
handle_IRQ_event+0x28/0x74
LR is at handle_level_irq+0x94/0xec
pc : [<c008cc30>] lr : [<c008e18c>] psr: 48000113
sp : c7eede90 ip : c7eedeb0 fp : c7eedeac
r10: 0000001d r9 : c0638ba8 r8 : 00000000
r7 : 0000005c r6 : 00000000 r5 : 0000005c r4 : c7a1b360
r3 : 00000000 r2 : 0000006e r1 : c7a1b360 r0 : 0000005c
Flags: nZcv IRQs on FIQs on Mode SVC_32 ISA ARM Segment user
Control: 10c5387d Table: 87f48018 DAC: 00000015
[<c003b370>] (show_regs+0x0/0x50) from [<c008c738>] (softlockup_tick+0x108/0x148)
r5:00000104 r4:000000c7
On Sun, Jun 27, 2010 at 6:36 PM, Michael Blizek <michi1@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
Hi!
Usually the stack trace that you have sent already contains the code which got
On 14:09 Sun 27 Jun , Harishkumar V wrote:
> MMU is available in ARM.
>
> if the same(cpu softlockup) exists on x86, how to handle this, u told in
> earlier mail,
>
> "This is only the stack trace of the softlockup check, not the code which
> got stuck", how to find out at which point, the code got struck, in x86.
stuck...
-Michi
--
programing a layer 3+4 network protocol for mesh networks
see http://michaelblizek.twilightparadox.com
--
Thanks and Regards,
Harish Kumar. V
