Hi, I am reading ldd3 and i am trying to understand how a circular buffer without locking works. If there is one writer and multiple readers. The writer has a pointer to head. the readers each have a pointer of their own to tail. Assumming the head can't circle on the tail in time, everything is peachy. However, in ldd3 the readers are sharing the tail pointer, how can this be alright? (See the code in ldd3->interrupt handling->Implementing a handler) At the very least you should somehow atomically grab the tail into a local var and also atomically increase the tail position all in one go so you won't get a race condition. Either that, or i did not understand the code. 10x. -- Regards, Tzahi. -- Tzahi Fadida Blog: http://tzahi.blogsite.org | Home Site: http://tzahi.webhop.info WARNING TO SPAMMERS: see at http://members.lycos.co.uk/my2nis/spamwarning.html -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ
