W dniu 2014-11-17 o 16:53, Uwe Kleine-König pisze:
Hello,
On Mon, Nov 17, 2014 at 11:05:51AM +0100, Richard Genoud wrote:
2014-11-17 10:59 GMT+01:00 Uwe Kleine-König <u.kleine-koenig@xxxxxxxxxxxxxx>:
Hello Richard,
So finally the prototypes would be:
int mctrl_gpio_request_irqs(struct mctrl_gpios*, struct
uart_port*, irqhandler_t);
void mctrl_gpio_free_irqs(struct mctrl_gpios*);
I think:
struct mctrl_gpios {
struct uart_port *port;
struct {
gpio_desc *gpio;
unsigned int irq;
I think it's just "int irq;" there
irqs are unsigned. Some functions returning an irq use "int", but
depending on who you ask this only for error reporting or a relict.
Use 0 for invalid/unused in mctrl_gpio*.
Yes. I tried to assign irq value in mctrl_gpio_init() only.
There was another issue if CONFIG_GPIOLIB is not defined but it looks mctrl_
disable/enable_ms()
and mctrl_ irq handler solve the problem.
Not sure there is a corresponding request_irq variant for that.
What would you propose?
In atmel_request_gpio_irq(), the function irq_set_status_flags(irq,
IRQ_NOAUTOEN); is used before request_irq to prevent the irq from
being enabled when requested.
I'm not sure this is allowed. How do you handle request_irq failing? (I
just checked: you don't.) Consider another thread just doing
request_irq($yourirq, ...) between
irq_set_status_flags(irq[i], IRQ_NOAUTOEN);
and
err = request_irq(irq[i], ...
well, in this case, request_irq() will fail and all the previously
requested irqs will be freed:
/*
* If something went wrong, rollback.
*/
while (err && (--i >= 0))
if (irq[i] >= 0)
free_irq(irq[i], port);
Just in case you didn't notice: Your statement is right, but for the
other caller to request_irq there is something fishy. He gets
IRQ_NOAUTOEN without being able to notice ...
Likely the gpio interrupts will never shared. We can say mctrl_gpio is
the only owner
of a gpio after a request. So should we worry that IRQ_NOAUTOEN is hidden?
best regards
Janusz
Best regards
Uwe
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