How about
#!/bin/bash
for ((i=1;i<11;i+=2))
do
echo $i
done
man bash shows the usage of the arithmetic for loop which I use all
the time to execute remote commands on systems whose hostnames vary
by an integer node number - e.g., host1, host2, host3, ... host128
On Thu, 1 Apr 2004, Jeff Largent wrote:
> And just to show another way:
>
> #!/bin/bash
>
> for i in `seq 1 10`; do
> if [ $((${i} % 2)) != 0 ]; then
> echo ${i}
> fi
> done
>
>
>
> Luca Ferrari wrote:
> > On Thursday 01 April 2004 02:45 Scott@Charter's cat walking on the keyboard
> > wrote:
> >
> >
> >>I can't get this bash script to work. It's suppose to print all odd
> >>numbers from 1 to 10.
> >>
> >>#!/usr/bin/bash
> >>
> >>LIMIT=10
> >>a=1
> >>
> >>while [ "$a" -le $LIMIT ]
> >>do
> >> if [ "$a" -eq $(1 3 5 7 9) ] <---------Something not right here.
> >
> >
> > This is an awkard way to print all odd numbers, have a look at this:
> >
> > #!/bin/bash
> >
> > LIMIT=10
> > a=1
> >
> > while test ${a} -lt ${LIMIT}
> > do
> > go=`expr ${a} % 2`
> > if test ${go} -ne 0
> > then
> > echo "Odd number ${a}"
> > fi
> >
> > a=`expr ${a} + 1`
> >
> > done
> >
> >
> > exit 0
> >
> >
> > In this example, if you change the LIMIT value to 100, the script will print
> > you all odds numbers, while in your example you have to put numbers by your
> > own. In perl it can result as:
> >
> > #!/usr/bin/perl
> >
> > $LIMIT=10;
> > $a=1;
> >
> > while( $a < $LIMIT ){
> > if( ($a % 2) !=0 ){
> > print "Odd number $a\n";
> > }
> > $a++;
> > }
> >
> > exit;
> >
> >
> > Luca
> >
> >
>
>
--
Charles D. (Chuck) Harding <charding@xxxxxxxx> Voice: 925-423-8879
Senior Computer Associate ICCD/SDD/ICRMG Fax: 925-423-8719
Lawrence Livermore National Laboratory Computation Directorate
Livermore, CA USA http://www.llnl.gov GPG Public Key ID: B9EB6601
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