bash question

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I can't get this bash script to work.  It's suppose to print all odd numbers
from 1 to 10.

#!/usr/bin/bash

LIMIT=10
a=1

while [ "$a" -le $LIMIT ]
do
  if [ "$a" -eq $(1 3 5 7 9) ]     <---------Something not right here.
    then
      echo -n "$a "
    fi

echo

let "a+=1"
done
echo; echo
exit 0


Can anyone figure out what I am doing wrong?  Can I also see the same thing
written in Perl?

Thanks for your help.



Scott D. Smallsreed
3030 Chipmunk Dr.
Washoe Valley, NV  89704
775.849.8411 Hm
775.849.8412 Fax
775.722.7773 Cell
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