/usr/bin/seq 1 2 10 works fine
Scott@Charter wrote:
I can't get this bash script to work. It's suppose to print all odd numbers from 1 to 10.
#!/usr/bin/bash
LIMIT=10 a=1
while [ "$a" -le $LIMIT ] do if [ "$a" -eq $(1 3 5 7 9) ] <---------Something not right here. then echo -n "$a " fi
echo
let "a+=1" done echo; echo exit 0
Can anyone figure out what I am doing wrong? Can I also see the same thing written in Perl?
Thanks for your help.
Scott D. Smallsreed
3030 Chipmunk Dr.
Washoe Valley, NV 89704
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775.849.8412 Fax
775.722.7773 Cell
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