Re: bash question

Jeff Largent <jlargent@xxxxxxxxxxxxxx> · Thu, 01 Apr 2004 09:58:05 -0500

And just to show another way:

#!/bin/bash

for i in `seq 1 10`; do
   if [ $((${i} % 2)) != 0 ]; then
      echo ${i}
   fi
done

Luca Ferrari wrote:
On Thursday 01 April 2004 02:45 Scott@Charter's cat walking on the keyboard  
wrote:

I can't get this bash script to work.  It's suppose to print all odd
numbers from 1 to 10.

#!/usr/bin/bash

LIMIT=10
a=1

while [ "$a" -le $LIMIT ]
do
 if [ "$a" -eq $(1 3 5 7 9) ]     <---------Something not right here.

This is an awkard way to print all odd numbers, have a look at this:

#!/bin/bash

LIMIT=10
a=1

while test ${a} -lt ${LIMIT}
do
  go=`expr ${a} % 2`
  if test ${go} -ne 0
      then
      echo "Odd number ${a}"
  fi

  a=`expr ${a} + 1`

done

exit 0

In this example, if you change the LIMIT value to 100, the script will print 
you all odds numbers, while in your example you have to put numbers by your 
own. In perl it can result as:

#!/usr/bin/perl

$LIMIT=10;
$a=1;

    while( $a < $LIMIT ){
        if( ($a % 2) !=0 ){
            print "Odd number $a\n";
        }
        $a++;
    }

exit;

Luca

--
Jeff Largent                   ImageLinks, Inc.
Sr System Admin                Melbourne, Fl 32935
(321) 253-0011                 fax: (321) 253-5559

-
: send the line "unsubscribe linux-admin" in
the body of a message to majordomo@xxxxxxxxxxxxxxx
More majordomo info at  http://vger.kernel.org/majordomo-info.html