hello mikea,
looks like there is something missing in your sourcecode, which you
should have provided. do you give any arguments to
mysql_fetch_array() ? Do you check if it is not false?
your code should look like this:
$sql = "SELECT * FROM example";
$result = mysql_query($sql,$db);
if ($result) {
$myrow=mysql_fetch_array($result);
} else {
echo "ERROR: SQL-query returned false!";
}
Robert
Mikea wrote:
I am getting the following errors when I execute a php script.
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result
resource
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource
What do I need to make this work? I am new to PHP. I read something about
mysql.class.php somewhere. Do I need that somewhere? Do I put an include
in the main script? Where does mysql.class.php go directory-wise?
I am sure I am not giving enough information and may not be explaining it
good enough. My apologies. Again, I am new at this.
I appreciate any help. Thank you in advance.
Mike
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