Hi everyone,
I'm new to working with PHP (coming from a ASP/VBScript background) and
I'm currently reading the book "Teach yourself PHP, mySQL, and Apache in
24 hours". The following code from the code from the book seems to be
causing an "undefined variable" error when run. Would any one be able
tell me why this is happening? Many thanks! Jim
Notice: Undefined variable: guess in numguess.php on line 27
<?php
$num_to_guess = 42;
$num_tries = ( isset($_POST["num_tries"])) ? $num_tries + 1 : 0;
//$guess = (isset($_POST["guess"])) ? $_POST["guess"] : 0;
$message = "";
if (!isset($_POST["guess"])) {
$message = "Welcome to the guessing machine!";
} elseif ( $_POST["guess"] > $num_to_guess) {
$message = "$_POST[guess] is too big! Try a smaller number";
} elseif ( $_POST["guess"] < $num_to_guess) {
$message = "$_POST[guess] is too small! Try a larger
number";
} else {
$message = "Well done!";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
<html xmlns="http://www.w3.org/1999/xhtml";>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"
>
</head>
<body>
<h1><?php print $message ?></h1>
Guess number: <?php print $num_tries ?>
<form action="<?php print $_SERVER["PHP_SELF"] ?>" method="post">
Type your guess here:
<input name="guess" type="text" value="<?php print $guess ?>">
<input name="num_tries" type="hidden" value="<?php print $num_tries ?>">
</form>
</body>
</html>
