Hi there, I want read a directory and open a file inside the directory, for example directory data contains of file: Computername.txt IPaddress.txt status.txt and i want search a file on the directory and open it, for example i want search file IPaddress.txt and when file IPaddress.txt found, i want open it, read and display the contains of the file. the script that i have is like this : <?php $find_file="name.txt"; if ($handle = opendir('C:\apache\htdocs')){ while (false !== ($file = readdir($handle))){ if ($file == $find_file){ echo " file found $file<br>"; // i want to open the file, but i am confuse with the file handle $handle_file = fopen ($find_file, "r"); while (!feof ($handle_file)){ $buffer = fgets($handle_file, 4096); echo "$buffer<br>"; } } } closedir($handle); } ?> this script does'nt run correctly i have an error message, "Warning: Supplied argument is not a valid File-Handle resource in c:\apache\htdocs\fseek\readdir.php on line 11" I confuse with the file handle, because is different with opening file like usually, what should i do...??? does any one can help me...?? Thanx idur --------------------------------- Do you Yahoo!? Yahoo! Photos - Get your photo on the big screen in Times Square