Re: newbie: how to return one iteration *per unique date (DAY!)* in a timestamp column?

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On Aug 4, 2009, at 6:21 PM, Chris <dmagick@xxxxxxxxx> wrote:

Govinda wrote:
I should have given an example ..

select count(*) as record_count, date(column_name) as date_field, 'my_table' as table_name
union all
select count(*) as record_count, date(column_name) as date_field, 'my_table_2' as table_name

and end up with:
count | date       | table_name
-------------------------------
5     | 2009-01-01 | table 1
10    | 2009-01-01 | table 2
Ben, Chris,
This is as far as I could get so far:
$query = "SELECT COUNT(*) AS landing_count, date (solarLandingDateTime) AS solarLandingDate, 't7solar_landingALIAS' AS t7solar_landing UNION ALL SELECT count(*) AS confirm_count, date (solarAweberConfDateTime) AS solarAweberConfDate, 'aweber_7solar_confirmALIAS' AS aweber_7solar_confirm UNION ALL SELECT count(*) AS thankyou_count, date(solarAWDateTime) AS solarAWDate, 'aweber_7solar_awALIAS' AS aweber_7solar_aw"; $foundUniqueDateROWS = mysql_query($query) or die("query failed: " .mysql_error());
giving this error:
query failed: Unknown column 'solarLandingDateTime' in 'field list'
but I most certainly do have a column named 'solarLandingDateTime' in the table named 't7solar_landing'.
So I am not sure what it's unhappy.

With a union the columns have to have the same name (or alias).

Eg:

SELECT
 COUNT(*) AS count,
 date(solarLandingDateTime) AS unique_date,
 't7solar_landingALIAS' AS origin
 FROM tablename
UNION ALL
SELECT
 count(*) AS count,
 date(solarAweberConfDateTime) AS unique_date,
 'aweber_7solar_confirmALIAS' AS origin
 FROM tablename

etc

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Correction the column names will come form the first query, but they need to be the same datatype in those columns. So if the first query has a date datatype, the subsequent queries must have date columns in the first position

Bastien

Sent from my iPod

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