Re: newbie: how to return one iteration *per unique date (DAY!)* in a timestamp column?

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I should have given an example ..

select count(*) as record_count, date(column_name) as date_field, 'my_table' as table_name
union all
select count(*) as record_count, date(column_name) as date_field, 'my_table_2' as table_name

and end up with:
count | date       | table_name
-------------------------------
5     | 2009-01-01 | table 1
10    | 2009-01-01 | table 2

Ben, Chris,

This is as far as I could get so far:

$query = "SELECT COUNT(*) AS landing_count, date(solarLandingDateTime) AS solarLandingDate, 't7solar_landingALIAS' AS t7solar_landing UNION ALL SELECT count(*) AS confirm_count, date(solarAweberConfDateTime) AS solarAweberConfDate, 'aweber_7solar_confirmALIAS' AS aweber_7solar_confirm UNION ALL SELECT count(*) AS thankyou_count, date(solarAWDateTime) AS solarAWDate, 'aweber_7solar_awALIAS' AS aweber_7solar_aw";

$foundUniqueDateROWS = mysql_query($query) or die("query failed: " .mysql_error());


giving this error:
query failed: Unknown column 'solarLandingDateTime' in 'field list'

but I most certainly do have a column named 'solarLandingDateTime' in the table named 't7solar_landing'.
So I am not sure what it's unhappy.
?

------------
John Butler (Govinda)
govinda.webdnatalk@xxxxxxxxx


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