Re: MySQL JOIN query : Seeking solution - Please Help

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Get those with transaction into a php array
Get those without transaction into a php array

Then use array_diff() (or one of its variants)

graeme.

jinxed wrote:

I am still new to this, but I turned the manual upside down, or at least I tried.

I am designing a payroll application by which payslips can be processed for each employee for each period.

The problem lays where I would like to display a list of employees that don't have transactions (payslips) for a particular period. I can easily display a list of employees that do have transactions (payslips) for a particular period. I tried reversing this, but it doesn't seem to work, or I'm missing something somewhere. Please help.

# Table structure for table `employees`

emp_id emp_num emp_title emp_surname emp_name emp_initials emp_termdate // etc.
INSERT INTO `employees` VALUES (1, 'EMP001', 'Mrs.', 'Surname1', 'Name1', 'N1.', '0000-00-00');
INSERT INTO `employees` VALUES (2, 'EMP002', 'Mr.', 'Surname2', 'Name2', 'N2.', '0000-00-00');
INSERT INTO `employees` VALUES (3, 'EMP003', 'Mr', 'Surname3', 'Name3', 'N3.', '0000-00-00');
INSERT INTO `employees` VALUES (4, 'EMP004', 'Mr.', 'Surname4', 'Name4', 'N4.', '2003-08-31');
INSERT INTO `employees` VALUES (5, 'EMP005', 'Mr.', 'Surname5', 'Name5', 'N5.', '2004-02-28');
INSERT INTO `employees` VALUES (6, 'EMP006', 'Mr.', 'Surname6', 'Name6', 'N6.', '0000-00-00');
INSERT INTO `employees` VALUES (7, 'EMP007', 'Mr.', 'Surname7', 'Name7', 'N7.', '0000-00-00');


# Table structure for table `payperiods`

pp_id    pp_period    pp_status
INSERT INTO `payperiods` VALUES (1, 'JAN 2004', 'inactive');
INSERT INTO `payperiods` VALUES (2, 'FEB 2004', 'active');

# Table structure for table `transactions`

CREATE TABLE `transactions` (
 `tran_id` int(11) NOT NULL auto_increment,
 `pp_id` int(11) NOT NULL default '0',
 `emp_id` int(11) NOT NULL default '0',
 `tran_basicsal` decimal(11,2) NOT NULL default '0.00',
 `tran_OT_rate` decimal(11,2) NOT NULL default '0.00',
 `tran_OT_qty` decimal(11,2) NOT NULL default '0.00',
 `tran_DT_rate` decimal(11,2) NOT NULL default '0.00',
 `tran_DT_qty` decimal(11,2) NOT NULL default '0.00',
 `tran_bonus` decimal(11,2) NOT NULL default '0.00',
 `tran_commission` decimal(11,2) NOT NULL default '0.00',
 `tran_travelall` decimal(11,2) NOT NULL default '0.00',
 `tran_cellall` decimal(11,2) NOT NULL default '0.00',
 `tran_leavepdout_days` decimal(11,2) NOT NULL default '0.00',
 `tran_leavepdout_rate` decimal(11,2) NOT NULL default '0.00',
 `tran_uif_emp` decimal(11,2) NOT NULL default '0.00',
 `tran_uif_com` decimal(11,2) NOT NULL default '0.00',
 `tran_sdl` decimal(11,2) NOT NULL default '0.00',
 `tran_paye` decimal(11,2) NOT NULL default '0.00',
 `tran_staffloan` decimal(11,2) NOT NULL default '0.00',
 `tran_unpaidleave_days` decimal(11,2) NOT NULL default '0.00',
 `tran_unpaidleave_rate` decimal(11,2) NOT NULL default '0.00',
 `tran_leave_taken` decimal(10,2) NOT NULL default '0.00',
 `tran_sl_taken` decimal(11,2) NOT NULL default '0.00',
 PRIMARY KEY  (`tran_id`)
) TYPE=MyISAM PACK_KEYS=0 AUTO_INCREMENT=12 ;

#
# Dumping data for table `transactions`
#

INSERT INTO `transactions` VALUES (6, 1, 1, '3500.00', '29.84', '1.00', '39.78', '1.00', '40.00', '10.00', '20.00', '30.00', '0.00', '159.12', '36.70', '36.70', '36.70', '366.96', '50.00', '0.00', '159.12', '0.00', '0.00');
INSERT INTO `transactions` VALUES (7, 1, 2, '2000.00', '17.04', '1.00', '22.72', '1.00', '40.00', '10.00', '20.00', '30.00', '0.00', '90.88', '21.40', '21.40', '21.40', '213.98', '50.00', '0.00', '90.88', '0.00', '0.00');
INSERT INTO `transactions` VALUES (8, 1, 3, '9000.00', '68.18', '1.00', '90.90', '1.00', '40.00', '10.00', '20.00', '30.00', '0.00', '409.05', '92.59', '92.59', '92.59', '925.91', '50.00', '0.00', '409.05', '0.00', '0.00');
INSERT INTO `transactions` VALUES (11, 2, 1, '3500.00', '29.84', '1.00', '39.78', '1.00', '40.00', '10.00', '20.00', '30.00', '0.00', '159.12', '36.70', '36.70', '36.70', '366.96', '50.00', '0.00', '159.12', '0.00', '0.00');
INSERT INTO `transactions` VALUES (10, 2, 7, '2200.00', '16.67', '1.00', '22.22', '1.00', '40.00', '10.00', '20.00', '30.00', '0.00', '99.99', '23.39', '23.39', '23.39', '233.89', '50.00', '0.00', '99.99', '0.00', '0.00');


# --------------------------------------------------------

My query is as follows:

<?php

// IF COUNT OF EMPLOYEES DIFFER WITH COUNT OF TRANSACTIONS, DO THIS
// DISPLAY ONLY EMPLOYEES THAT DON'T HAVE TRANSACTIONS FOR THE CURRENT ("active") PERIOD.
else {
$t1 = 'employees';
$t2 = 'transactions';
$selectempquery = mysql_query("SELECT DISTINCT $t1.*, $t2.emp_id
FROM $t1
LEFT JOIN $t2 ON $t1.emp_id=$t2.emp_id
WHERE NOT $t1.emp_termdate


AND ($t2.pp_id != '$pp_id' OR $t2.pp_id IS NULL)"); // This doesn't work right

// if i replace the above AND with:
AND $t2.emp_id IS NULL"); // it won't return any rows if employees have transactions in other periods, // because it searches the ON $t1.emp_id = $t2.emp_id and doesn't
// concider the period at all


// Combining both these in the query just refuses to return any results.

while ($row = @mysql_fetch_array($selectempquery)) {
$variable3=$row['emp_num'];
$variable4=$row['emp_title'];
$variable5=$row['emp_initials'];
$variable6=$row['emp_surname'];
echo "<tr><td width=75 height=21>&nbsp;$variable3 </td><td width=225> <a href=".WEB_ROOT."procpayslip1.php?pp_id=$pp_id&emp_num=$variable3>$variable4 $variable5 $variable6</a></td></tr>";
}
}
?>


I concidered first selecting transactions that do exist in the period, but then I am not sure how to put this into an array in order to exclude it. A subquery doesn't work either and I'm using MySQL 4.0.24 will be upgrading soon to MySQL 4.1.11

The query substring looked like this:

$t1 = 'employees';
$t2 = 'transactions';
$selectempquery = mysql_query("SELECT DISTINCT $t1.*, $t2.emp_id FROM $t1 LEFT JOIN $t2 ON $t2.emp_id = $t2.emp_id WHERE $t2.emp_id != (SELECT `emp_id` FROM `transactions` WHERE `pp_id` = '$pp_id')");


What is wrong here? It returns no rows and I would expect it to.

Please help




-- Experience is a good teacher, but she sends in terrific bills.

Minna Antrim

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