<form>
<select name="person1">
<option value="1">Joe Smith</option>
etc.
</select>
<input type="radio" name="person1yn" value="Yes"> Y <input type="radio" name="person1yn" value="No"> N
<select name="person2">
<option value="1">Joe Smith</option>
etc.
</select>
<input type="radio" name="person2yn" value="Yes"> Y <input type="radio" name="person2yn" value="No"> N
and so on... <input type="submit"> </form>
On Saturday, March 29, 2003, at 05:25 PM, John W. Holmes wrote:
ofI was wondering what is the best way to insert multiple records into a table? Here is the scenario...
I have a form which has 5 select menus as part of the data that gets entered. Most of the data goes into a table called tbl_reports. Eachtothese 5 menus contains the same list of people (from tbl_people). I have another table which I am calling tbl_report_people which I wantfilledINSERT a record for each person that is selected for any new report (I hope this is making sense). So for example, a new report form isout and submitted. 3 of the people selects are used, so I need to add to the tbl_report_people table the record_id and person_id for each person selected.
The fastest way will be to create your INSERT dynamically and do them all at once. The format would be:
INSERT INTO table (column1, column2) VALUES (value1,value2),(value11,value22),(value111,value222)
If you're getting record_id and person_id from a form, you can just loop
through them and create each (value,value) part and then add on the
beginning. Without seeing your actual form, that'd be about the best
advice I can give.
---John W. Holmes...
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