Re: query .. please review

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 








Hello just u r not concat the variablle

test this one

$qry = "SELECT * FROM cityrates WHERE id=.'$city_rec'";

your code--------
$qry = "SELECT * FROM cityrates WHERE id = '$city_rec'";





--- In php-objects@xxxxxxxxxxxxxxx, "musika_astig" <mjdiose@...> wrote:
>
> --- In php-objects@xxxxxxxxxxxxxxx, Reji Jayan <for_rejijayan@> wrote:
> >
> > 44               $qry = "SELECT * FROM cityrates WHERE id = '$city_rec'";
> > 45            $rec1 = mysql_query($qry);
> > 46            $rs1=mysql_fetch_array($rec1);
> > 47         
> > 48            $ship_county=$rs1['County'];
> > 49            $ship_tax = rs_1['Tax']; 
> > 50            $ship_city=$rs_1['City'];
> >    
> > got .. and im getting the error ...... 
> > 
> > Parse error: parse error in 
> > E:\wamp\www\blah-bhal\vieworders.php on line 49
> > 
> > 
> > i dont know wht hapnd to that line ...... 
> > 
> > is it any reserved word .. any solution to solve this 
> > 
> > ( not on renaming the field on the table .. if so)
> > 
> >          
> > --------------------------------------------------------------------
> > 
> > 
> > 
> > 
> >       Looking for local information? Find it on Yahoo! Local http://in.local.yahoo.com/
> > 
> > [Non-text portions of this message have been removed]
> >
> 
> 
> 
> it think you forgot to write a dollar sign
> something like this -> $ship_tax = $rs_1['Tax'];
>



[Index of Archives]     [PHP Home]     [PHP Users]     [PHP Soap]     [Kernel Newbies]     [Yosemite]     [Yosemite Campsites]

  Powered by Linux