you can try it
$qry = "SELECT * FROM cityrates WHERE id = '".$city_rec."'";
$rec1 = mysql_query($qry);
$rs1=mysql_fetch_array($rec1);
$ship_county=$rs1['County'];
$ship_tax = rs_1['Tax'];
$ship_city=$rs_1['City'];
On Tue, Jul 21, 2009 at 9:19 AM, solanboy <solanboy@xxxxxxxxx> wrote:
>
>
> Line Should be
>
> $ship_tax = $rs1['Tax'];
> $ship_city=$rs1['City'];
>
> --- In php-objects@xxxxxxxxxxxxxxx <php-objects%40yahoogroups.com>,
> "musika_astig" <mjdiose@...> wrote:
> >
> > --- In php-objects@xxxxxxxxxxxxxxx <php-objects%40yahoogroups.com>, Reji
> Jayan <for_rejijayan@> wrote:
> > >
> > > 44 $qry = "SELECT * FROM cityrates WHERE id =
> '$city_rec'";
> > > 45 $rec1 = mysql_query($qry);
> > > 46 $rs1=mysql_fetch_array($rec1);
> > > 47
> > > 48 $ship_county=$rs1['County'];
> > > 49 $ship_tax = rs_1['Tax'];
> > > 50 $ship_city=$rs_1['City'];
> > >
> > > got .. and im getting the error ......
> > >
> > > Parse error: parse error in
> > > E:\wamp\www\blah-bhal\vieworders.php on line 49
> > >
> > >
> > > i dont know wht hapnd to that line ......
> > >
> > > is it any reserved word .. any solution to solve this
> > >
> > > ( not on renaming the field on the table .. if so)
> > >
> > >
> > > ----------------------------------------------------------
> > >
> > >
> > >
> > >
> > > Looking for local information? Find it on Yahoo! Local
> http://in.local.yahoo.com/
> > >
> > > [Non-text portions of this message have been removed]
> > >
> >
> >
> >
> > it think you forgot to write a dollar sign
> > something like this -> $ship_tax = $rs_1['Tax'];
> >
>
>
>
[Non-text portions of this message have been removed]
