I missed the original e-mail, but it looks like: 1) You're missing the dollar sign ($) in front of rs_1 on line 49. 2) That variable should be $rs1, not $rs_1, so it will give you problems on line 50 as well. -- Joe On Jul 21, 2009, at 12:57 AM, musika_astig wrote: > --- In php-objects@xxxxxxxxxxxxxxx, Reji Jayan <for_rejijayan@...> > wrote: > > > > 44 $qry = "SELECT * FROM cityrates WHERE id = > '$city_rec'"; > > 45 $rec1 = mysql_query($qry); > > 46 $rs1=mysql_fetch_array($rec1); > > 47 > > 48 $ship_county=$rs1['County']; > > 49 $ship_tax = rs_1['Tax']; > > 50 $ship_city=$rs_1['City']; > > > > got .. and im getting the error ...... > > > > Parse error: parse error in > > E:\wamp\www\blah-bhal\vieworders.php on line 49 > > > > > > i dont know wht hapnd to that line ...... > > > > is it any reserved word .. any solution to solve this > > > > ( not on renaming the field on the table .. if so) [Non-text portions of this message have been removed]