This should do it (untested) :-
$stringData = $headers['Content-Disposition'];
$arrayFilename = explode("=",$stringData);
$imageName = replace("\"","",$arrayFilename[1]);
-----Original Message-----
From: php-objects@xxxxxxxxxxxxxxx [mailto:php-objects@xxxxxxxxxxxxxxx] On
Behalf Of Ali Jamali
Sent: 25 November 2008 12:37
To: php-objects@xxxxxxxxxxxxxxx
Subject: Re: Converting CGI+Perl to PHP Help
I need the file name because the camera give images name by different setting
, For example user wanted add date & time to file or some specific name they
declare and image must same in the server with that . Any way I try to do
that
I use this line
$stringData = $headers['Content-Disposition'];
and out put is :
attachment; filename="image.jpg"
So Is there any way I just take the filename or not ?
I just need image.jpg
I will become very perfect if you suggestion something to fetch the name .
Thanks
Ali
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