Have you thinking in use session to save your data values ???
On Sat, Feb 23, 2008 at 12:44 PM, Bedri Ozgur Guler <bedriguler@xxxxxxxxx>
wrote:
> You may use the following code. The code is not an inteligent solution
> to your problem I guess but it had always worked for me. You can use cURL's
> post options as well. The other way is to use AJAX posting method of course.
>
> CODE:
> <form name="DuplicateUserForm" action="duplicateuser.php" method="post">
> <input type="hidden" name="duplicateuser" value="<?php echo $username;
> ?>">
> </form>
>
> <form name="ThankYouForm" action="thankyou.php" method="post">
> <input type="hidden" name="fname" value="<?php echo $fname; ?>">
> </form>
>
> <?php
> if($usernamerows > 0)
> {
> ?>
> <script language="Javascript">
> document.DuplicateUserForm.submit();
> </script>
> <?php
> }
> else
> {
> ?>
> <script language="Javascript">
> document.ThankYouForm.submit();
> </script>
> <?php
>
> }
> ?>
>
> That's it. Then you can use either $_POST[] or $_REQUEST[] in either
> thankyou.php or duplicateuser.php.
>
> Gratz...
> Bedri
>
> Sudhakar <finals27@xxxxxxxxx <finals27%40yahoo.com>> wrote: i have an if
> else situation wherein if a user registers with a name
> that is already available in the database i redirect them to
> duplicateuser.php or else redirect to thankyou.php
>
> presently i am able to pass value of a variable $username as part of
> the url and i am able to read using GET by doing so the value
> appears in the browser address bar and i would like to use hidden
> and also be able to read this value
>
> following is the code i am presently using
>
> if($usernamerows > 0)
> {
> header("Location: duplicateuser.php? duplicateuser=".$username);
>
> }
> else
> {
> header("Location: thankyou.php?fname=".$fname);
> }
>
> how can i use hidden so that the url does not get appended in the
> address bar and still the read the value of the variables i want to
> pass and how should i read the variables in the other pages, is it
> $_POST[]
>
> i tried using this code just before the header() statement but it
> does not work and i get an error.
>
> echo "<input type ='hidden' name='duplicateuser' value='$username'>";
> echo "<input type ='hidden' name='fname' value='$fname'>";
>
> please advice.
>
> thanks.
>
>
>
>
>
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