On 2/23/2011 8:48 PM, Ron Piggott wrote:
Is there a way to make this syntax:
$checking_answer = $answer_reference_2;
Equal to:
$checking_answer = $answer_reference_ . ($i + 1);
(where $i = 1)
making $checking_answer take on the value of $answer_reference_2 ?
I am trying to develop a web app quiz and I need to test the users answers.
Ron
The Verse of the Day
âEncouragement from Godâs Wordâ
http://www.TheVerseOfTheDay.info
Give this a try
<?php
# Variable Variables Test
$id_0 = 'zero';
$id_1 = 'one';
$id_2 = 'two';
$id_3 = 'three';
for ( $i=0; $i<4; $i++ ) {
echo ${'id_'.$i};
}
?>
--
Jim Lucas
http://www.cmsws.com
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