On 11-02-23 11:48 PM, Ron Piggott wrote:
Is there a way to make this syntax:
$checking_answer = $answer_reference_2;
Equal to:
$checking_answer = $answer_reference_ . ($i + 1);
(where $i = 1)
making $checking_answer take on the value of $answer_reference_2 ?
I am trying to develop a web app quiz and I need to test the users answers.
<?php
$checking_answer = ${'answer_reference_'.($i + 1)};
?>
Cheers,
Rob.
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