Is there a way to make this syntax: $checking_answer = $answer_reference_2; Equal to: $checking_answer = $answer_reference_ . ($i + 1); (where $i = 1) making $checking_answer take on the value of $answer_reference_2 ? I am trying to develop a web app quiz and I need to test the users answers. Ron The Verse of the Day âEncouragement from Godâs Wordâ http://www.TheVerseOfTheDay.info