Re: version_compare

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On Thu, Sep 30, 2010 at 9:43 PM, Brian Smither <bhsmither@xxxxxxxxx> wrote:
>
> I found this code...
> if (version_compare(PHP_VERSION, '5.2.0', '>=')) {
It means condition (PHP_VERSION >= 5.2.0)

> Â$text=filter_var($text, FILTER_SANITIZE_URL);
> }
>
> ...to be questionable.
>
> Under what conditions would version_compare() return true, yet the filter_var() be undefined? Because that's what is happening.
>
> Thank you.
>
>
>
>
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